A train running between two stations A and B arrives at its destination 15minutes late, when its speed is 45 km/hr. and 36 minutes late when its speed is 36 km/hr. find the distance between the stations A and B?

ANS:

Let ‘x’ km be the distance between the station A and B.

Speed of the train = 45 km/hr

Time taken =x/45 hours

Since the train is late by 15 minutes =1/4

Actual time =(x/45 -1/4)hr-------(1)

Time taken when the speed is 36 km/hr=x/36 hrs

Now, since the train is late by 36 min i.e.,36/60=3/5

actual time= (x/36-3/5)hrs ---------(2)

 Equating (1) and (2), we get x/45 -1/4 =x/36 -3/5 

∴ x/45 -1/4 =x/36 -3/5 

x=63km